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Popular >

y^'+100y=0

Solution

y^{^{'}} + 100 y = 0

Solution

y = e^{- 100 t + c_{1}}

Solution steps

y^{'} (t) + 100 y = 0

Solve separable ODE:

y = e^{- 100 t + c_{1}}

y = e^{- 100 t + c_{1}}

Popular Examples

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\int 6 x + 5 d x

implicit sin(y)=5x^3-5 implicit derivative

sin (y) = 5 x^{3} - 5

tangent of f(x)=x^2-x+1,\at x=-1 tangent of

f (x) = x^{2} - x + 1, at x = - 1

Frequently Asked Questions (FAQ)

What is the solution for y^'+100y=0 ?
The solution for y^'+100y=0 is y=e^{-100t+c_{1}}