What is the derivative of 1+sqrt(2x) ?

The derivative of 1+sqrt(2x) is 1/(sqrt(2)\sqrt{x)}

What is the first derivative of 1+sqrt(2x) ?

The first derivative of 1+sqrt(2x) is 1/(sqrt(2)\sqrt{x)}

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\frac{d}{d x} (1 + 2 x)

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (1 + 2 x)

Simplify

1 + 2 x : 1 + 2 x

= \frac{d}{d x} (1 + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (2 x)

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 x) = \frac{1}{2 x}

= 0 + \frac{1}{2 x}

Simplify

= \frac{1}{2 x}

\frac{\partial}{\partial x} (x y^{2} + x)

\frac{d y}{d x} - y x - y^{2} = 0

\int \frac{2}{v ^{2}} d v

(sin^{3} (x))^{^{'}}

((ln (x))^{2})^{^{'}}

What is the derivative of 1+sqrt(2x) ?
The derivative of 1+sqrt(2x) is 1/(sqrt(2)\sqrt{x)}
What is the first derivative of 1+sqrt(2x) ?
The first derivative of 1+sqrt(2x) is 1/(sqrt(2)\sqrt{x)}