What is (\partial)/(\partial x)(xy^2+x) ?

The answer to (\partial)/(\partial x)(xy^2+x) is y^2+1

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(\partial)/(\partial x)(xy^2+x)

\frac{\partial}{\partial x} (x y^{2} + x)

y^{2} + 1

Solution steps

\frac{\partial}{\partial x} (x y^{2} + x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y^{2}) + \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (x y^{2}) = y^{2}

\frac{\partial}{\partial x} (x) = 1

= y^{2} + 1

\frac{d y}{d x} - y x - y^{2} = 0

\int \frac{2}{v ^{2}} d v

(sin^{3} (x))^{^{'}}

y = 9 arctan (x + 1 + x^{2})

((ln (x))^{2})^{^{'}}

What is (\partial)/(\partial x)(xy^2+x) ?
The answer to (\partial)/(\partial x)(xy^2+x) is y^2+1