What is the ((ln(x))^2)^' ?

The ((ln(x))^2)^' is (2ln(x))/x

What is the first ((ln(x))^2)^' ?

The first ((ln(x))^2)^' is (2ln(x))/x

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((ln (x))^{2})^{^{'}}

\frac{2 ln ( x )}{x}

Solution steps

((ln (x))^{2})^{'}

Apply the chain rule:

2 ln (x) (ln (x))^{'}

= 2 ln (x) (ln (x))^{'}

(ln (x))^{'} = \frac{1}{x}

= 2 ln (x) \frac{1}{x}

Simplify

2 ln (x) \frac{1}{x} : \frac{2 ln ( x )}{x}

= \frac{2 ln ( x )}{x}

x \to - 8 lim (\frac{8 - ∣ x ∣}{8 + x})

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