What is the derivative of g(x)=3x^4 ?

The derivative of g(x)=3x^4 is 12x^3

What is the first derivative of g(x)=3x^4 ?

The first derivative of g(x)=3x^4 is 12x^3

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derivative of

g (x) = 3 x^{4}

12 x^{3}

Solution steps

\frac{d}{d x} (3 x^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot 4 x^{4 - 1}

Simplify

= 12 x^{3}

f (x) = \frac{3}{x}, (5, \frac{3}{5})

\int x^{4} e^{7 x} d x

\int \frac{x ^{2} - 3}{x ( x ^{2} - 1 )} d x

\int_{0}^{π} 4 sec^{2} (\frac{x}{4}) d x

\frac{\partial}{\partial x} (2 x^{3} cos (x y))

What is the derivative of g(x)=3x^4 ?
The derivative of g(x)=3x^4 is 12x^3
What is the first derivative of g(x)=3x^4 ?
The first derivative of g(x)=3x^4 is 12x^3