What is the derivative of 8x+9xe^x ?

The derivative of 8x+9xe^x is 8+9(e^x+e^xx)

What is the first derivative of 8x+9xe^x ?

The first derivative of 8x+9xe^x is 8+9(e^x+e^xx)

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derivative of

8 x + 9 x e^{x}

8 + 9 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (8 x + 9 x e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) + \frac{d}{d x} (9 x e^{x})

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (9 x e^{x}) = 9 (e^{x} + e^{x} x)

= 8 + 9 (e^{x} + e^{x} x)

\int 2 ln (t) d t

y^{^{'}} = 1 - 7 x^{2}

\int \frac{x - 2}{x + 3} d x

\int cos (\frac{nπ x}{L}) d x

\frac{d}{d x} (2 (x)^{4})

What is the derivative of 8x+9xe^x ?
The derivative of 8x+9xe^x is 8+9(e^x+e^xx)
What is the first derivative of 8x+9xe^x ?
The first derivative of 8x+9xe^x is 8+9(e^x+e^xx)