What is laplacetransform 2-0.5e^{-10t} ?

The answer to laplacetransform 2-0.5e^{-10t} is 2/s-(0.5)/(s+10)

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laplacetransform 2-0.5e^{-10t}

laplace transform

2 - 0.5 e^{- 10 t}

\frac{2}{s} - \frac{0.5}{s + 10}

Solution steps

L {2 - 0.5 e^{- 10 t}}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {2} - 0.5 L {e^{- 10 t}}

L {2} : \frac{2}{s}

L {e^{- 10 t}} : \frac{1}{s + 10}

= \frac{2}{s} - 0.5 \cdot \frac{1}{s + 10}

Refine

\frac{2}{s} - 0.5 \frac{1}{s + 10} : \frac{2}{s} - \frac{0.5}{s + 10}

= \frac{2}{s} - \frac{0.5}{s + 10}

f (x) = \frac{x ^{2} - 1}{x - 1}

x \to - 5 lim (\frac{4 ( 2 x + 3 ) ^{2} - 196}{x + 5})

\frac{d}{d x} (ln (\frac{( 2 x + 1 ) ^{2}}{( x - 1 )}))

\frac{( 2 s + 1 )}{s ^{2} + 10 + 25}

What is laplacetransform 2-0.5e^{-10t} ?
The answer to laplacetransform 2-0.5e^{-10t} is 2/s-(0.5)/(s+10)