What is the tangent of x^2-7x+7 ?

The tangent of x^2-7x+7 is y=(2a_{0}-7)x-a_{0}^2+7

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tangent of x^2-7x+7

tangent of

x^{2} - 7 x + 7

y = (2 a_{0} - 7) x - a_{0}^{2} + 7

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - 7 a_{0} + 7)

Find the slope of

y = x^{2} - 7 x + 7 : \frac{d y}{d x} = 2 x - 7

Compute the slope of

y = x^{2} - 7 x + 7

x = a_{0} : m = 2 a_{0} - 7

Find the line with slope m=

2 a_{0} - 7

and passing through

(a_{0}, a_{0}^{2} - 7 a_{0} + 7) : y = (2 a_{0} - 7) x - a_{0}^{2} + 7

y = (2 a_{0} - 7) x - a_{0}^{2} + 7

\frac{\partial}{\partial y} (\frac{3 x}{y})

\frac{d}{d x} (2 - cos (x))

\frac{\partial}{\partial x} (x y + 6 x)

\int \frac{cos ^{5} ( x )}{sin ( x )} d x

n = 1 \sum \infty \frac{1}{n n}

What is the tangent of x^2-7x+7 ?
The tangent of x^2-7x+7 is y=(2a_{0}-7)x-a_{0}^2+7