What is the integral of (2/(x^3)+3/(x^2)+5) ?

The integral of (2/(x^3)+3/(x^2)+5) is -1/(x^2)-3/x+5x+C

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integral of (2/(x^3)+3/(x^2)+5)

\int (\frac{2}{x ^{3}} + \frac{3}{x ^{2}} + 5) d x

- \frac{1}{x ^{2}} - \frac{3}{x} + 5 x + C

Solution steps

\int \frac{2}{x ^{3}} + \frac{3}{x ^{2}} + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{x ^{3}} d x + \int \frac{3}{x ^{2}} d x + \int 5 d x

\int \frac{2}{x ^{3}} d x = - \frac{1}{x ^{2}}

\int \frac{3}{x ^{2}} d x = - \frac{3}{x}

\int 5 d x = 5 x

= - \frac{1}{x ^{2}} - \frac{3}{x} + 5 x

Add a constant to the solution

= - \frac{1}{x ^{2}} - \frac{3}{x} + 5 x + C

\frac{e ^{- s}}{s ( s + 2 )}

x \to 0 lim (x^{2} cos (\frac{9}{x}))

\int 14 - 20 - 3 16 - 2 x d x

\int \frac{2 x}{9 x ^{2} - 12 x + 8} d x

y = x + x, (9, 12)

What is the integral of (2/(x^3)+3/(x^2)+5) ?
The integral of (2/(x^3)+3/(x^2)+5) is -1/(x^2)-3/x+5x+C