What is the limit as x approaches 0 of x^2cos(9/x) ?

The limit as x approaches 0 of x^2cos(9/x) is 0

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limit as x approaches 0 of x^2cos(9/x)

x \to 0 lim (x^{2} cos (\frac{9}{x}))

0

Solution steps

x \to 0 lim (x^{2} cos (\frac{9}{x}))

Apply the Squeeze Theorem:

0

= 0

\int 14 - 20 - 3 16 - 2 x d x

\int \frac{2 x}{9 x ^{2} - 12 x + 8} d x

y = x + x, (9, 12)

\frac{d}{d x} (\frac{x ^{3}}{12} + \frac{2}{3} x^{- 3})

\frac{d}{d x} (- 8 e^{- \frac{x}{10}} - 40)

What is the limit as x approaches 0 of x^2cos(9/x) ?
The limit as x approaches 0 of x^2cos(9/x) is 0