What is the tangent of f(x)=(1+2x)^{10},(0,1) ?

The tangent of f(x)=(1+2x)^{10},(0,1) is y=20x+1

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tangent of f(x)=(1+2x)^{10},(0,1)

tangent of

f (x) = (1 + 2 x)^{10}, (0, 1)

y = 20 x + 1

Solution steps

Find the slope of

f (x) = (1 + 2 x)^{10} : \frac{df ( x )}{d x} = 20 (1 + 2 x)^{9}

Compute the slope of

f (x) = (1 + 2 x)^{10}

(0, 1) : m = 20

Find the line with slope m=

20

and passing through

(0, 1) : y = 20 x + 1

y = 20 x + 1

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What is the tangent of f(x)=(1+2x)^{10},(0,1) ?
The tangent of f(x)=(1+2x)^{10},(0,1) is y=20x+1