What is the solution for (dy)/(dx)=((2x(y-1)))/(x^2+3),y(1)=9 ?

The solution for (dy)/(dx)=((2x(y-1)))/(x^2+3),y(1)=9 is y=2x^2+7

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(dy)/(dx)=((2x(y-1)))/(x^2+3),y(1)=9

\frac{d y}{d x} = \frac{( 2 x ( y - 1 ) )}{x ^{2} + 3}, y (1) = 9

y = 2 x^{2} + 7

Solution steps

\frac{d y}{d x} = \frac{( 2 x ( y - 1 ) )}{x ^{2} + 3}

Solve separable ODE:

y = 2 x^{2} + 7

y = 2 x^{2} + 7

(\frac{x ^{2}}{( x - 2 ) ^{2}})^{^{'}}

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\frac{d y}{d x} = x^{2} - \frac{1}{2} y

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\frac{d}{d x} (x^{4} e^{- 3 x})

What is the solution for (dy)/(dx)=((2x(y-1)))/(x^2+3),y(1)=9 ?
The solution for (dy)/(dx)=((2x(y-1)))/(x^2+3),y(1)=9 is y=2x^2+7