What is (\partial)/(\partial x)(2sin(6x)cos(4y)) ?

The answer to (\partial)/(\partial x)(2sin(6x)cos(4y)) is 12cos(6x)cos(4y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2sin(6x)cos(4y))

\frac{\partial}{\partial x} (2 sin (6 x) cos (4 y))

12 cos (6 x) cos (4 y)

Solution steps

\frac{\partial}{\partial x} (2 sin (6 x) cos (4 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 cos (4 y) \frac{\partial}{\partial x} (sin (6 x))

Apply the chain rule:

cos (6 x) \frac{\partial}{\partial x} (6 x)

= cos (6 x) \frac{\partial}{\partial x} (6 x)

\frac{\partial}{\partial x} (6 x) = 6

= 2 cos (4 y) cos (6 x) \cdot 6

Simplify

= 12 cos (6 x) cos (4 y)

y = \frac{x}{5} - 4

\frac{d}{d x} (\frac{4}{x ^{4}} - 4 5 x)

\int x^{2} x^{3} + 27 d x

\frac{d}{d y} (e^{- 2 y})

\frac{d}{d x} (x^{5} - x^{3} + 3)

What is (\partial)/(\partial x)(2sin(6x)cos(4y)) ?
The answer to (\partial)/(\partial x)(2sin(6x)cos(4y)) is 12cos(6x)cos(4y)