en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+xy=xy^2

Solution

y^{^{'}} + x y = x y^{2}

Solution

y = \frac{1}{1 - e ^{\frac{x ^{2}}{2} + c_{1}}}

Solution steps

y^{'} (x) + x y = x y^{2}

Solve separable ODE:

y = \frac{1}{1 - e ^{\frac{x ^{2}}{2} + c_{1}}}

y = \frac{1}{1 - e ^{\frac{x ^{2}}{2} + c_{1}}}

Popular Examples

integral from a to b of 1/(x^3)

\int_{a}^{b} \frac{1}{x ^{3}} d x

derivative of f(x)50-sqrt(x)derivative of

f (x) 50 - x

derivative of f(x)=6+2/x+3/(x^2),x=x derivative of

f (x) = 6 + \frac{2}{x} + \frac{3}{x ^{2}}, x = x

tangent of f(x)=2x^2-3x+3 tangent of

f (x) = 2 x^{2} - 3 x + 3

integral of (x^2+2x+3)/(x^3+3x^2+9x)

\int \frac{x ^{2} + 2 x + 3}{x ^{3} + 3 x ^{2} + 9 x} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+xy=xy^2 ?
The solution for y^'+xy=xy^2 is y= 1/(1-e^{\frac{x^2){2}+c_{1}}}