What is the solution for (dy)/(dx)+9xy=8x ?

The solution for (dy)/(dx)+9xy=8x is y=(e^{(-9x^2+c_{1})/2})/(9)+8/9

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(dy)/(dx)+9xy=8x

\frac{d y}{d x} + 9 x y = 8 x

y = \frac{e ^{\frac{- 9 x ^{2} + c _{1}}{2}}}{9} + \frac{8}{9}

Solution steps

\frac{d y}{d x} + 9 x y = 8 x

Solve separable ODE:

y = \frac{e ^{\frac{- 9 x ^{2} + c _{1}}{2}}}{9} + \frac{8}{9}

y = \frac{e ^{\frac{- 9 x ^{2} + c _{1}}{2}}}{9} + \frac{8}{9}

\int_{0}^{6} \frac{π}{9} (36 - y^{2}) d y

(sin (x) - x cos (x))^{^{'}}

y^{^{'}} = 20 x y

\int 3 x sin (\frac{1}{6} x) d x

f (x) = - \frac{1}{x}

What is the solution for (dy)/(dx)+9xy=8x ?
The solution for (dy)/(dx)+9xy=8x is y=(e^{(-9x^2+c_{1})/2})/(9)+8/9