What is area 5cos(7x),5-5cos(7x) ?

The answer to area 5cos(7x),5-5cos(7x) is (10sqrt(3))/7+(20pi)/(21)

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area 5cos(7x),5-5cos(7x)

area

5 cos (7 x), 5 - 5 cos (7 x)

\frac{10 3}{7} + \frac{20 π}{21}

Decimal Notation

5.46635 \dots

Solution steps

Apply the area formula:

\int_{\frac{π}{21}}^{\frac{5 π}{21}} ∣ 5 cos (7 x) - (5 - 5 cos (7 x)) ∣ d x

Solve

\int_{\frac{π}{21}}^{\frac{5 π}{21}} ∣ 5 cos (7 x) - (5 - 5 cos (7 x)) ∣ d x : \frac{10 3}{7} + \frac{20 π}{21}

The area is:

= \frac{10 3}{7} + \frac{20 π}{21}

\frac{d}{d x} (6 e^{2 x})

x \to 8 lim (f (x))

\int \frac{1}{x ^{2} + x - 2} d x

\frac{\partial}{\partial x} (7 y - 5 x)

\int sin (1 - 2 x) d x

What is area 5cos(7x),5-5cos(7x) ?
The answer to area 5cos(7x),5-5cos(7x) is (10sqrt(3))/7+(20pi)/(21)