What is the integral of sin(1-2x) ?

The integral of sin(1-2x) is 1/2 cos(1-2x)+C

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integral of sin(1-2x)

\int sin (1 - 2 x) d x

\frac{1}{2} cos (1 - 2 x) + C

Solution steps

\int sin (1 - 2 x) d x

Apply u-substitution

: \int - \frac{1}{2} sin (u) d u

= \int - \frac{1}{2} sin (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= - \frac{1}{2} (- cos (u))

Substitute back

u = 1 - 2 x

= - \frac{1}{2} (- cos (1 - 2 x))

Simplify

= \frac{1}{2} cos (1 - 2 x)

Add a constant to the solution

= \frac{1}{2} cos (1 - 2 x) + C

\frac{d y}{d x} = 1 + x + y^{2} + x y^{2}

x \to 2 + lim (\frac{2}{x - 2})

x \to 1 lim (7 x + 5)

\frac{d y}{d x} = (y - 1) (y + 1), y (0) = 3

e^{3 x}, e^{7 x}, x = 1

What is the integral of sin(1-2x) ?
The integral of sin(1-2x) is 1/2 cos(1-2x)+C