What is the integral of 1/(sqrt(4+(u+3))) ?

The integral of 1/(sqrt(4+(u+3))) is 2sqrt(u+7)+C

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integral of 1/(sqrt(4+(u+3)))

\int \frac{1}{4 + ( u + 3 )} d u

2 u + 7 + C

Solution steps

\int \frac{1}{4 + u + 3} d u

Simplify

= \int \frac{1}{u + 7} d u

Apply u-substitution

: \int 2 d v

= \int 2 d v

Integral of a constant:

\int a d x = a x

= 2 v

Substitute back

v = u + 7

= 2 u + 7

Add a constant to the solution

= 2 u + 7 + C

y = ln (8 x)

y^{^{''}} - 7 y^{^{'}} = 5 t

x \to 0 lim (\frac{x}{sin ( 4 x )})

\int_{2}^{4} \frac{1}{x ^{2} + 1} d x

\frac{\partial}{\partial x} (y^{7 x})

What is the integral of 1/(sqrt(4+(u+3))) ?
The integral of 1/(sqrt(4+(u+3))) is 2sqrt(u+7)+C