What is the solution for (dy}{dx}=\frac{x^2+2y)/x ,y(1)=2 ?

The solution for (dy}{dx}=\frac{x^2+2y)/x ,y(1)=2 is y=ln(x)x^2+2x^2

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(dy}{dx}=\frac{x^2+2y)/x ,y(1)=2

\frac{d y}{d x} = \frac{x ^{2} + 2 y}{x}, y (1) = 2

y = ln (x) x^{2} + 2 x^{2}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} + 2 y}{x}

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y = ln (x) x^{2} + 2 x^{2}

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What is the solution for (dy}{dx}=\frac{x^2+2y)/x ,y(1)=2 ?
The solution for (dy}{dx}=\frac{x^2+2y)/x ,y(1)=2 is y=ln(x)x^2+2x^2