What is the tangent of f(x)=x-5cos(x),\at x=0 ?

The tangent of f(x)=x-5cos(x),\at x=0 is y=x-5

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tangent of f(x)=x-5cos(x),\at x=0

tangent of

f (x) = x - 5 cos (x), at x = 0

y = x - 5

Solution steps

Find the tangent point:

(0, - 5)

Find the slope of

f (x) = x - 5 cos (x) : \frac{df ( x )}{d x} = 1 + 5 sin (x)

Compute the slope of

f (x) = x - 5 cos (x)

x = 0 : m = 1

Find the line with slope m=

1

and passing through

(0, - 5) : y = x - 5

y = x - 5

n = 0 \sum \infty (x - 10)^{n}

f (x) = \frac{1}{3 - x}

\int_{0}^{3} 2 d x

\frac{14}{ln ( x )}

\frac{7}{( s - 7 ) ^{8}}

What is the tangent of f(x)=x-5cos(x),\at x=0 ?
The tangent of f(x)=x-5cos(x),\at x=0 is y=x-5