What is the derivative of y=(5x^2+4)/(x+3) ?

The derivative of y=(5x^2+4)/(x+3) is (5x^2+30x-4)/((x+3)^2)

What is the first derivative of y=(5x^2+4)/(x+3) ?

The first derivative of y=(5x^2+4)/(x+3) is (5x^2+30x-4)/((x+3)^2)

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derivative of

y = \frac{5 x ^{2} + 4}{x + 3}

\frac{5 x ^{2} + 30 x - 4}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5 x ^{2} + 4}{x + 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 5 x ^{2} + 4 ) ( x + 3 ) - \frac{d}{d x} ( x + 3 ) ( 5 x ^{2} + 4 )}{( x + 3 ) ^{2}}

\frac{d}{d x} (5 x^{2} + 4) = 10 x

\frac{d}{d x} (x + 3) = 1

= \frac{10 x ( x + 3 ) - 1 \cdot ( 5 x ^{2} + 4 )}{( x + 3 ) ^{2}}

Simplify

\frac{10 x ( x + 3 ) - 1 \cdot ( 5 x ^{2} + 4 )}{( x + 3 ) ^{2}} : \frac{5 x ^{2} + 30 x - 4}{( x + 3 ) ^{2}}

= \frac{5 x ^{2} + 30 x - 4}{( x + 3 ) ^{2}}

\int_{0}^{\frac{π}{4}} x sin (8 x) d x

x^{2} ln (9 + x)

y = 2 x, (32, 8)

\int cos (14 x) cos (5 x) d x

\int \frac{tan ( x ) + 1}{cos ^{2} ( x )} d x

What is the derivative of y=(5x^2+4)/(x+3) ?
The derivative of y=(5x^2+4)/(x+3) is (5x^2+30x-4)/((x+3)^2)
What is the first derivative of y=(5x^2+4)/(x+3) ?
The first derivative of y=(5x^2+4)/(x+3) is (5x^2+30x-4)/((x+3)^2)