What is integral of (-8cos(-2))d ?

The answer to integral of (-8cos(-2))d is (-8cos(2)d+C)d

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integral of (-8cos(-2))d

\int (- 8 cos (- 2)) ddd

(- 8 cos (2) d + C) d

Solution steps

\int - 8 cos (- 2) ddd

\int - 8 cos (- 2) dd = - 8 cos (2) d + C

= (- 8 cos (2) d + C) d

\int \frac{1}{x ^{4} x ^{2} + 5} d x

\frac{\partial}{\partial x} (sin (2 x + 3 y + z))

x \to 3 lim (ln (x + 3))

\int \frac{2 x ^{2} - 7 x - 1}{( x - 1 ) ( x + 1 ) ^{2}} d x

y^{^{'}} = \frac{5 x ^{3} + y ^{3}}{x y ^{2}}

What is integral of (-8cos(-2))d ?
The answer to integral of (-8cos(-2))d is (-8cos(2)d+C)d