What is the derivative of F(x)=3x^4-65x^3 ?

The derivative of F(x)=3x^4-65x^3 is 12x^3-195x^2

What is the first derivative of F(x)=3x^4-65x^3 ?

The first derivative of F(x)=3x^4-65x^3 is 12x^3-195x^2

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derivative of

F (x) = 3 x^{4} - 65 x^{3}

12 x^{3} - 195 x^{2}

Solution steps

\frac{d}{d x} (3 x^{4} - 65 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) - \frac{d}{d x} (65 x^{3})

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (65 x^{3}) = 195 x^{2}

= 12 x^{3} - 195 x^{2}

t + 1

\int \frac{( 1 + cos ( 2 x ) )}{2} d x

y = \frac{2 x}{1 - cot ( x )}

\frac{\partial}{\partial x} (3 e^{x y + 9})

f (x) = \frac{3 - 2 x}{3 + 2 x}

What is the derivative of F(x)=3x^4-65x^3 ?
The derivative of F(x)=3x^4-65x^3 is 12x^3-195x^2
What is the first derivative of F(x)=3x^4-65x^3 ?
The first derivative of F(x)=3x^4-65x^3 is 12x^3-195x^2