What is the derivative of f(x)=(3-2x)/(3+2x) ?

The derivative of f(x)=(3-2x)/(3+2x) is -(12)/((3+2x)^2)

What is the first derivative of f(x)=(3-2x)/(3+2x) ?

The first derivative of f(x)=(3-2x)/(3+2x) is -(12)/((3+2x)^2)

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derivative of

f (x) = \frac{3 - 2 x}{3 + 2 x}

- \frac{12}{( 3 + 2 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 - 2 x}{3 + 2 x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 - 2 x ) ( 3 + 2 x ) - \frac{d}{d x} ( 3 + 2 x ) ( 3 - 2 x )}{( 3 + 2 x ) ^{2}}

\frac{d}{d x} (3 - 2 x) = - 2

\frac{d}{d x} (3 + 2 x) = 2

= \frac{( - 2 ) ( 3 + 2 x ) - 2 ( 3 - 2 x )}{( 3 + 2 x ) ^{2}}

Simplify

\frac{( - 2 ) ( 3 + 2 x ) - 2 ( 3 - 2 x )}{( 3 + 2 x ) ^{2}} : - \frac{12}{( 3 + 2 x ) ^{2}}

= - \frac{12}{( 3 + 2 x ) ^{2}}

x \frac{d y}{d x} = y + x^{2} - y^{2}

x \to - 6 lim (2 x + 3)

y = (2 x^{4} + 7)^{2}

\int \frac{y}{y ^{2} - 2 y - 3} d y

\frac{d}{d x} (f (x) (g (x)))

What is the derivative of f(x)=(3-2x)/(3+2x) ?
The derivative of f(x)=(3-2x)/(3+2x) is -(12)/((3+2x)^2)
What is the first derivative of f(x)=(3-2x)/(3+2x) ?
The first derivative of f(x)=(3-2x)/(3+2x) is -(12)/((3+2x)^2)