What is the integral from 0 to 0.6 of 10000x ?

The integral from 0 to 0.6 of 10000x is 1800

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integral from 0 to 0.6 of 10000x

\int_{0}^{0.6} 10000 x d x

1800

Solution steps

\int_{0}^{0.6} 10000 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10000 \cdot \int_{0}^{0.6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.6}

= 10000 [\frac{x ^{2}}{2}]_{0}^{0.6}

Simplify

= 10000 [0.5 x^{2}]_{0}^{0.6}

Compute the boundaries:

0.18

= 10000 \cdot 0.18

Simplify

= 1800

9 x^{3}

(x \cdot x - 1) y^{^{'}} - x y (1 - y) = 0

\frac{d}{d t} (\frac{3 t ^{2}}{1 + 4 t ^{2} + 9 t ^{4}})

\int e^{x^{2}} x^{3} d x

\frac{d}{d x} (a r (x) cos (e^{x}))

What is the integral from 0 to 0.6 of 10000x ?
The integral from 0 to 0.6 of 10000x is 1800