What is the derivative of sqrt(3+6x) ?

The derivative of sqrt(3+6x) is 3/(sqrt(3+6x))

What is the first derivative of sqrt(3+6x) ?

The first derivative of sqrt(3+6x) is 3/(sqrt(3+6x))

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\frac{d}{d x} (3 + 6 x)

\frac{3}{3 + 6 x}

Solution steps

\frac{d}{d x} (3 + 6 x)

Apply the chain rule:

\frac{1}{2 3 + 6 x} \frac{d}{d x} (3 + 6 x)

= \frac{1}{2 3 + 6 x} \frac{d}{d x} (3 + 6 x)

\frac{d}{d x} (3 + 6 x) = 6

= \frac{1}{2 3 + 6 x} \cdot 6

Simplify

\frac{1}{2 3 + 6 x} \cdot 6 : \frac{3}{3 + 6 x}

= \frac{3}{3 + 6 x}

\int_{0}^{9} x - \frac{1}{3} x d x

\frac{d y}{d t} = - 2 y

\frac{d}{d x} (\frac{1 + x ^{2} + x ^{4}}{1 + x + x ^{2}})

\int \frac{x + 3}{x ( x - 1 ) ( x + 4 )} d x

What is the derivative of sqrt(3+6x) ?
The derivative of sqrt(3+6x) is 3/(sqrt(3+6x))
What is the first derivative of sqrt(3+6x) ?
The first derivative of sqrt(3+6x) is 3/(sqrt(3+6x))