What is the derivative of (x^2+3x/(-6)) ?

The derivative of (x^2+3x/(-6)) is -1/6 (2x+3)

What is the first derivative of (x^2+3x/(-6)) ?

The first derivative of (x^2+3x/(-6)) is -1/6 (2x+3)

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\frac{d}{d x} (\frac{x ^{2} + 3 x}{- 6})

- \frac{1}{6} (2 x + 3)

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 3 x}{- 6})

Simplify

\frac{x ^{2} + 3 x}{- 6} : - \frac{x ^{2} + 3 x}{6}

= \frac{d}{d x} (- \frac{x ^{2} + 3 x}{6})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{6} \frac{d}{d x} (x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{1}{6} (\frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= - \frac{1}{6} (2 x + 3)

\frac{d y}{d x} - 4 y = \frac{48 x}{y ^{2}}

\frac{\partial}{\partial x} (ln (x^{6} + y^{7}))

\frac{d}{d x} (3 arcsin (x^{4}))

\int \frac{2 x ^{3}}{1 + x ^{4}} d x

What is the derivative of (x^2+3x/(-6)) ?
The derivative of (x^2+3x/(-6)) is -1/6 (2x+3)
What is the first derivative of (x^2+3x/(-6)) ?
The first derivative of (x^2+3x/(-6)) is -1/6 (2x+3)