What is partialfraction (x^2)/(1-x^2) ?

The solution to partialfraction (x^2)/(1-x^2) is -1+1/(2(x+1))-1/(2(x-1))

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partialfraction (x^2)/(1-x^2)

partial fractions

\frac{x ^{2}}{1 - x ^{2}}

- 1 + \frac{1}{2 ( x + 1 )} - \frac{1}{2 ( x - 1 )}

Solution steps

\frac{x ^{2}}{1 - x ^{2}}

Long division

\frac{x ^{2}}{1 - x ^{2}} : - 1 + \frac{1}{- x ^{2} + 1}

= - 1 + \frac{1}{- x ^{2} + 1}

Continue partial fractions on remainder:

\frac{1}{1 - x ^{2}}

Take the partial fraction of

\frac{1}{1 - x ^{2}} : \frac{1}{2 ( x + 1 )} - \frac{1}{2 ( x - 1 )}

- 1 + \frac{1}{2 ( x + 1 )} - \frac{1}{2 ( x - 1 )}

\frac{\partial}{\partial x} (x^{3} y + x cos (y))

\frac{d y}{d x} = \frac{1}{2} y^{3}

\frac{\partial}{\partial x} (cos^{7} (x^{9} y^{8}))

\frac{1}{e ^{x}}

(y^{3} - 1) e^{x} + 3 y^{2} (e^{x} + 1) \frac{d y}{d x} = 0, y (0) = 2

What is partialfraction (x^2)/(1-x^2) ?
The solution to partialfraction (x^2)/(1-x^2) is -1+1/(2(x+1))-1/(2(x-1))