What is laplacetransform t-e^{-3t} ?

The answer to laplacetransform t-e^{-3t} is 1/(s^2)-1/(s+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform t-e^{-3t}

laplace transform

t - e^{- 3 t}

\frac{1}{s ^{2}} - \frac{1}{s + 3}

Solution steps

L {t - e^{- 3 t}}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t} - L {e^{- 3 t}}

L {t} : \frac{1}{s ^{2}}

L {e^{- 3 t}} : \frac{1}{s + 3}

= \frac{1}{s ^{2}} - \frac{1}{s + 3}

\frac{\partial}{\partial x} (\frac{- 3}{y - 3 x})

2 x^{2} + x - 1, at a = 0

\int_{0}^{3} x^{3} - x d x

f (x) = (4 x^{4} - 7 x^{2} + 6)

(x + \frac{1}{x})^{3}

What is laplacetransform t-e^{-3t} ?
The answer to laplacetransform t-e^{-3t} is 1/(s^2)-1/(s+3)