What is the derivative of f(x)=(4x^4-7x^2+6) ?

The derivative of f(x)=(4x^4-7x^2+6) is 16x^3-14x

What is the first derivative of f(x)=(4x^4-7x^2+6) ?

The first derivative of f(x)=(4x^4-7x^2+6) is 16x^3-14x

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derivative of

f (x) = (4 x^{4} - 7 x^{2} + 6)

16 x^{3} - 14 x

Solution steps

\frac{d}{d x} ((4 x^{4} - 7 x^{2} + 6))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{4}) - \frac{d}{d x} (7 x^{2}) + \frac{d}{d x} (6)

\frac{d}{d x} (4 x^{4}) = 16 x^{3}

\frac{d}{d x} (7 x^{2}) = 14 x

\frac{d}{d x} (6) = 0

= 16 x^{3} - 14 x + 0

Simplify

= 16 x^{3} - 14 x

(x + \frac{1}{x})^{3}

x \to 2 lim (5 x^{3} - 9 x^{2} + 7)

\int x^{3} \cdot cos (x) d x

x ln (x) = y (1 + 8 + y^{2}) y^{^{'}} (x), y (1) = 1

\frac{d}{d x} (in (x^{2} + 1))

What is the derivative of f(x)=(4x^4-7x^2+6) ?
The derivative of f(x)=(4x^4-7x^2+6) is 16x^3-14x
What is the first derivative of f(x)=(4x^4-7x^2+6) ?
The first derivative of f(x)=(4x^4-7x^2+6) is 16x^3-14x