What is (\partial)/(\partial y)(y/(1+x^2)) ?

The answer to (\partial)/(\partial y)(y/(1+x^2)) is 1/(1+x^2)

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(\partial)/(\partial y)(y/(1+x^2))

\frac{\partial}{\partial y} (\frac{y}{1 + x ^{2}})

\frac{1}{1 + x ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{y}{1 + x ^{2}})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{1 + x ^{2}} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= \frac{1}{1 + x ^{2}} \cdot 1

Simplify

= \frac{1}{1 + x ^{2}}

\int \frac{1}{x + 2} d x

\frac{d}{d θ} (2 cos (θ))

\frac{d y}{d x} = (4 x^{2} + 3 x + 2) (y + 5)

\int 1.5 x d x

(x^{2} + 4), (- x^{2} - 1), x = - 2, x = 3

What is (\partial)/(\partial y)(y/(1+x^2)) ?
The answer to (\partial)/(\partial y)(y/(1+x^2)) is 1/(1+x^2)