What is the derivative of 16cos(2x) ?

The derivative of 16cos(2x) is -32sin(2x)

What is the first derivative of 16cos(2x) ?

The first derivative of 16cos(2x) is -32sin(2x)

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derivative of

16 cos (2 x)

- 32 sin (2 x)

Solution steps

\frac{d}{d x} (16 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 16 (- sin (2 x) \cdot 2)

Simplify

= - 32 sin (2 x)

y - y^{^{''}} = (1 + π^{2}) sin (π x)

\int \frac{1}{1 + 11 x} d x

y = (5 x + 1)^{4} (4 x + 3)^{- 2}

x \to 4 lim (x \cdot 5)

x \to \infty lim (x + \frac{1}{x})

What is the derivative of 16cos(2x) ?
The derivative of 16cos(2x) is -32sin(2x)
What is the first derivative of 16cos(2x) ?
The first derivative of 16cos(2x) is -32sin(2x)