What is the derivative of 2x^2+3x-4 ?

The derivative of 2x^2+3x-4 is 4x+3

What is the first derivative of 2x^2+3x-4 ?

The first derivative of 2x^2+3x-4 is 4x+3

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derivative of

2 x^{2} + 3 x - 4

4 x + 3

Solution steps

\frac{d}{d x} (2 x^{2} + 3 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 4 x + 3 - 0

Simplify

= 4 x + 3

\frac{d}{d x} (ln (π x))

\int \frac{5}{( x + 1 ) ^{2}} d x

f (t) = t 4 - t^{2}

(y^{2} + 2 x y) d x - x^{2} d y = 0

\frac{d y}{d x} = \frac{3 x ^{2} + 4 x + 2}{2 ( y - 1 )}, y (0) = - 1

What is the derivative of 2x^2+3x-4 ?
The derivative of 2x^2+3x-4 is 4x+3
What is the first derivative of 2x^2+3x-4 ?
The first derivative of 2x^2+3x-4 is 4x+3