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Popular >

(y^2+2xy)dx-x^2dy=0

Solution

(y^{2} + 2 x y) d x - x^{2} d y = 0

Solution

y = \frac{x ^{2}}{- x + c _{1}}

Solution steps

(y^{2} + 2 x y) d x - x^{2} d y = 0

Solve Bernoulli ODE:

y = \frac{x ^{2}}{- x + c _{1}}

y = \frac{x ^{2}}{- x + c _{1}}

Popular Examples

(dy)/(dx)=(3x^2+4x+2)/(2(y-1)),y(0)=-1

\frac{d y}{d x} = \frac{3 x ^{2} + 4 x + 2}{2 ( y - 1 )}, y (0) = - 1

y^'=sin^2(x-y+1)

y^{^{'}} = sin^{2} (x - y + 1)

\frac{d y}{d x} + 2 y = x

integral of 1/(sqrt(144-x^2))

\int \frac{1}{144 - x ^{2}} d x

integral of arccot(8y)

\int arccot (8 y) d y

Frequently Asked Questions (FAQ)

What is the solution for (y^2+2xy)dx-x^2dy=0 ?
The solution for (y^2+2xy)dx-x^2dy=0 is y=(x^2)/(-x+c_{1)}