What is the derivative of (-16x^2+36^2) ?

The derivative of (-16x^2+36^2) is -64x(-16x^2+36)

What is the first derivative of (-16x^2+36^2) ?

The first derivative of (-16x^2+36^2) is -64x(-16x^2+36)

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\frac{d}{d x} ((- 16 x^{2} + 36)^{2})

- 64 x (- 16 x^{2} + 36)

Solution steps

\frac{d}{d x} ((- 16 x^{2} + 36)^{2})

Apply the chain rule:

2 (- 16 x^{2} + 36) \frac{d}{d x} (- 16 x^{2} + 36)

= 2 (- 16 x^{2} + 36) \frac{d}{d x} (- 16 x^{2} + 36)

\frac{d}{d x} (- 16 x^{2} + 36) = - 32 x

= 2 (- 16 x^{2} + 36) (- 32 x)

Simplify

= - 64 x (- 16 x^{2} + 36)

\frac{d}{d x} (\frac{x}{1 - ln ( x - 3 )})

x \to 0 lim (\frac{4 ^{x} - 2 ^{x}}{x})

\frac{d}{d x} (a - b x^{2})

\int_{1}^{2} (2 x - 3)^{2} d x

y^{^{'}} + 7 y = t + e^{- 4 t}

What is the derivative of (-16x^2+36^2) ?
The derivative of (-16x^2+36^2) is -64x(-16x^2+36)
What is the first derivative of (-16x^2+36^2) ?
The first derivative of (-16x^2+36^2) is -64x(-16x^2+36)