What is area e^{2x},e^{6x},x=1 ?

The answer to area e^{2x},e^{6x},x=1 is (e^6-3e^2+2)/6

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area e^{2x},e^{6x},x=1

area

e^{2 x}, e^{6 x}, x = 1

\frac{e ^{6} - 3 e ^{2} + 2}{6}

Decimal Notation

63.87693 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} e^{2 x} - e^{6 x} d x

Solve

\int_{0}^{1} e^{2 x} - e^{6 x} d x : \frac{e ^{6} - 3 e ^{2} + 2}{6}

The area is:

= \frac{e ^{6} - 3 e ^{2} + 2}{6}

\frac{d}{d x} (- 2 x - 4)

x \to 1 lim (\frac{cos ( π x )}{3})

f^{^{'}} (x) = e^{3 x + 2} - 3 x^{2}

\int x y^{2} - x^{2} d x

7 x, 8 x^{2}

What is area e^{2x},e^{6x},x=1 ?
The answer to area e^{2x},e^{6x},x=1 is (e^6-3e^2+2)/6