What is the limit as x approaches-0 of 1/x ?

The limit as x approaches-0 of 1/x is diverges

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limit as x approaches-0 of 1/x

x \to - 0 lim (\frac{1}{x})

diverges

Solution steps

x \to - 0 lim (\frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 0 + lim (\frac{1}{x}) = \infty

x \to - 0 - lim (\frac{1}{x}) = - \infty

= diverges

y = x, y = x^{2} + 1, x = - 1, x = 2

y^{^{'}} = \frac{1}{y ^{2}}

y = cos (x), at x = 2 π

\frac{d}{d x} (- 8 sin (8 x))

\frac{d}{d x} ((5 x^{3} + 8 x - 3)^{\frac{3}{2}})

What is the limit as x approaches-0 of 1/x ?
The limit as x approaches-0 of 1/x is diverges