What is the solution for y^'=5ysin(4x),y(pi/8)=3 ?

The solution for y^'=5ysin(4x),y(pi/8)=3 is y=3e^{-5/4 cos(4x)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=5ysin(4x),y(pi/8)=3

y^{^{'}} = 5 y sin (4 x), y (\frac{π}{8}) = 3

y = 3 e^{- \frac{5}{4} c o s (4 x)}

Solution steps

y^{'} (x) = 5 y sin (4 x)

Solve separable ODE:

y = 3 e^{- \frac{5}{4} c o s (4 x)}

y = 3 e^{- \frac{5}{4} c o s (4 x)}

n = 1 \sum \infty \frac{1}{π ^{n}}

x \to 0 lim (x (\frac{1}{2 x}))

y^{^{''}} + 2 y^{^{'}} - 63 y = 0

(x - 4)^{n}, 4

\int \frac{x}{x ^{2} + 25} d x

What is the solution for y^'=5ysin(4x),y(pi/8)=3 ?
The solution for y^'=5ysin(4x),y(pi/8)=3 is y=3e^{-5/4 cos(4x)}