What is the solution for y^{''}+2y^'-63y=0 ?

The solution for y^{''}+2y^'-63y=0 is y=c_{1}e^{7t}+c_{2}e^{-9t}

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y^{''}+2y^'-63y=0

y^{^{''}} + 2 y^{^{'}} - 63 y = 0

y = c_{1} e^{7 t} + c_{2} e^{- 9 t}

Solution steps

y^{''} (t) + 2 y^{'} (t) - 63 y = 0

Solve linear ODE:

y = c_{1} e^{7 t} + c_{2} e^{- 9 t}

y = c_{1} e^{7 t} + c_{2} e^{- 9 t}

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\int \frac{x}{x ^{2} + 25} d x

y = cos (x), y = 1 - cos (x), 0 \leq x \leq π

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What is the solution for y^{''}+2y^'-63y=0 ?
The solution for y^{''}+2y^'-63y=0 is y=c_{1}e^{7t}+c_{2}e^{-9t}