What is area y=cos(x),y=1-cos(x),0<= x<= pi ?

The answer to area y=cos(x),y=1-cos(x),0<= x<= pi is -(2pi)/3+pi+2sqrt(3)

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area y=cos(x),y=1-cos(x),0<= x<= pi

area

y = cos (x), y = 1 - cos (x), 0 \leq x \leq π

- \frac{2 π}{3} + π + 23

Solution steps

Apply the area formula:

\int_{0}^{π} ∣ cos (x) - (1 - cos (x)) ∣ d x

Solve

\int_{0}^{π} ∣ cos (x) - (1 - cos (x)) ∣ d x : - \frac{2 π}{3} + π + 23

The area is:

= - \frac{2 π}{3} + π + 23

\int \frac{24}{1 + 25 r ^{2}} d r

2 e^{3 t}

8 (\frac{1}{s ^{5}})

y = x^{3} + 2 x, y = 3 x

\int e^{- x} sin (x) + 1 d x

What is area y=cos(x),y=1-cos(x),0<= x<= pi ?
The answer to area y=cos(x),y=1-cos(x),0<= x<= pi is -(2pi)/3+pi+2sqrt(3)