What is inverse oflaplace 8(1/(s^5)) ?

The answer to inverse oflaplace 8(1/(s^5)) is (t^4)/3

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inverse oflaplace 8(1/(s^5))

inverse laplace

8 (\frac{1}{s ^{5}})

\frac{t ^{4}}{3}

Solution steps

L^{- 1} {8 (\frac{1}{s ^{5}})}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 8 L^{- 1} {\frac{1}{s ^{5}}}

L^{- 1} {\frac{1}{s ^{5}}} : \frac{t ^{4}}{24}

= 8 \cdot \frac{t ^{4}}{24}

Refine

8 \frac{t ^{4}}{24} : \frac{t ^{4}}{3}

= \frac{t ^{4}}{3}

y = x^{3} + 2 x, y = 3 x

\int e^{- x} sin (x) + 1 d x

\int \frac{1}{( x + 2 ) ( x - 5 )} d x

(1 + x)^{\frac{- 3}{2}}

n = 1 \sum \infty \frac{2 n}{3 n + 1}

What is inverse oflaplace 8(1/(s^5)) ?
The answer to inverse oflaplace 8(1/(s^5)) is (t^4)/3