What is the sum from n=1 to infinity of (2n)/(3n+1) ?

The sum from n=1 to infinity of (2n)/(3n+1) is diverges

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sum from n=1 to infinity of (2n)/(3n+1)

n = 1 \sum \infty \frac{2 n}{3 n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{2 n}{3 n + 1}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 1 \sum \infty \frac{n}{3 n + 1}

Apply Series Divergence Test:

diverges

= 2 diverges

= diverges

2 x^{2} \frac{d y}{d x} = 3 x y + y^{2}

\frac{d}{d t} (cos (t) - t sin (t))

cos (sin (tan (3 x)))

\frac{2}{5 ( s + 1 ) ^{2} - 80}

What is the sum from n=1 to infinity of (2n)/(3n+1) ?
The sum from n=1 to infinity of (2n)/(3n+1) is diverges