What is the tangent of y=2x^2,(-1,2) ?

The tangent of y=2x^2,(-1,2) is y=-4x-2

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tangent of y=2x^2,(-1,2)

tangent of

y = 2 x^{2}, (- 1, 2)

y = - 4 x - 2

Solution steps

Find the slope of

y = 2 x^{2} : \frac{d y}{d x} = 4 x

Compute the slope of

y = 2 x^{2}

(- 1, 2) : m = - 4

Find the line with slope m=

- 4

and passing through

(- 1, 2) : y = - 4 x - 2

y = - 4 x - 2

\int x^{2} e^{- \frac{2 x}{a}} d x

x \to 0 lim (x \cdot cos (\frac{1}{x}))

3 x^{2} - 5 x + 2

x \to - 9 - lim (\frac{1}{( x + 9 ) ^{2}})

\frac{d}{d x} ((9 x + 3) e^{2 x^{2} + 3})