What is the limit as x approaches-9-of 1/((x+9)^2) ?

The limit as x approaches-9-of 1/((x+9)^2) is infinity

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limit as x approaches-9-of 1/((x+9)^2)

x \to - 9 - lim (\frac{1}{( x + 9 ) ^{2}})

\infty

Solution steps

x \to - 9 - lim (\frac{1}{( x + 9 ) ^{2}})

For

x

approaching

- 9

from the left

, x < - 9 \Rightarrow (x + 9)^{2} > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\frac{d}{d x} ((9 x + 3) e^{2 x^{2} + 3})

(y - \frac{y}{x ^{2}} e^{\frac{y}{x}}) d x + (x + \frac{1}{x} e^{\frac{y}{x}}) d y = 0

\frac{d}{d x} (\frac{x ^{2} + 5 x - 1}{x ^{2}})

- 3 + 12 x - 3 x^{2}

x \to - 1 lim (3 x^{3})

What is the limit as x approaches-9-of 1/((x+9)^2) ?
The limit as x approaches-9-of 1/((x+9)^2) is infinity