What is the derivative of (x^2+5x-1/(x^2)) ?

The derivative of (x^2+5x-1/(x^2)) is (-5x+2)/(x^3)

What is the first derivative of (x^2+5x-1/(x^2)) ?

The first derivative of (x^2+5x-1/(x^2)) is (-5x+2)/(x^3)

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\frac{d}{d x} (\frac{x ^{2} + 5 x - 1}{x ^{2}})

\frac{- 5 x + 2}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 5 x - 1}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} + 5 x - 1 ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( x ^{2} + 5 x - 1 )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (x^{2} + 5 x - 1) = 2 x + 5

\frac{d}{d x} (x^{2}) = 2 x

= \frac{( 2 x + 5 ) x ^{2} - 2 x ( x ^{2} + 5 x - 1 )}{( x ^{2} ) ^{2}}

Simplify

\frac{( 2 x + 5 ) x ^{2} - 2 x ( x ^{2} + 5 x - 1 )}{( x ^{2} ) ^{2}} : \frac{- 5 x + 2}{x ^{3}}

= \frac{- 5 x + 2}{x ^{3}}

- 3 + 12 x - 3 x^{2}

x \to - 1 lim (3 x^{3})

\int sec^{3} (u) d u

\int \frac{1}{( 16 + x ^{2} ) ^{3}} d x

- 6 x = 10 - y - 36 x = 48 - 6 y

What is the derivative of (x^2+5x-1/(x^2)) ?
The derivative of (x^2+5x-1/(x^2)) is (-5x+2)/(x^3)
What is the first derivative of (x^2+5x-1/(x^2)) ?
The first derivative of (x^2+5x-1/(x^2)) is (-5x+2)/(x^3)