What is the derivative of sqrt(1-6x) ?

The derivative of sqrt(1-6x) is -3/(sqrt(1-6x))

What is the first derivative of sqrt(1-6x) ?

The first derivative of sqrt(1-6x) is -3/(sqrt(1-6x))

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derivative of

1 - 6 x

- \frac{3}{1 - 6 x}

Solution steps

\frac{d}{d x} (1 - 6 x)

Apply the chain rule:

\frac{1}{2 1 - 6 x} \frac{d}{d x} (1 - 6 x)

= \frac{1}{2 1 - 6 x} \frac{d}{d x} (1 - 6 x)

\frac{d}{d x} (1 - 6 x) = - 6

= \frac{1}{2 1 - 6 x} (- 6)

Simplify

\frac{1}{2 1 - 6 x} (- 6) : - \frac{3}{1 - 6 x}

= - \frac{3}{1 - 6 x}

y = 3 x, y = \frac{3 x}{4}

\frac{d}{d x} (arcsec (3 x^{2} + 1))

x \to \infty lim (n c^{n})

x \to 0 lim (\frac{3 x}{x + 5})

y^{^{'}} + y = e^{6 t}, y (0) = - 1

What is the derivative of sqrt(1-6x) ?
The derivative of sqrt(1-6x) is -3/(sqrt(1-6x))
What is the first derivative of sqrt(1-6x) ?
The first derivative of sqrt(1-6x) is -3/(sqrt(1-6x))