What is the integral of 4sqrt(3-2x-x^2) ?

The integral of 4sqrt(3-2x-x^2) is 8(arcsin(1/2 (x+1))+1/2 sin(2arcsin(1/2 (x+1))))+C

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integral of 4sqrt(3-2x-x^2)

\int 4 3 - 2 x - x^{2} d x

8 (arcsin (\frac{1}{2} (x + 1)) + \frac{1}{2} sin (2 arcsin (\frac{1}{2} (x + 1)))) + C

Solution steps

\int 4 3 - 2 x - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int 3 - 2 x - x^{2} d x

Complete the square

3 - 2 x - x^{2} : - (x + 1)^{2} + 4

= 4 \cdot \int - (x + 1)^{2} + 4 d x

Apply u-substitution

: \int - u^{2} + 4 d u

= 4 \cdot \int - u^{2} + 4 d u

Apply Trigonometric Substitution

: \int 4 cos^{2} (v) d v

= 4 \cdot \int 4 cos^{2} (v) d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot 4 \cdot \int cos^{2} (v) d v

Rewrite using trig identities

= 4 \cdot 4 \cdot \int \frac{1 + cos ( 2 v )}{2} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot 4 \cdot \frac{1}{2} \cdot \int 1 + cos (2 v) d v

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 4 \cdot 4 \cdot \frac{1}{2} (\int 1 d v + \int cos (2 v) d v)

\int 1 d v = v

\int cos (2 v) d v = \frac{1}{2} sin (2 v)

= 4 \cdot 4 \cdot \frac{1}{2} (v + \frac{1}{2} sin (2 v))

Substitute back

= 4 \cdot 4 \cdot \frac{1}{2} (arcsin (\frac{1}{2} (x + 1)) + \frac{1}{2} sin (2 arcsin (\frac{1}{2} (x + 1))))

Simplify

4 \cdot 4 \cdot \frac{1}{2} (arcsin (\frac{1}{2} (x + 1)) + \frac{1}{2} sin (2 arcsin (\frac{1}{2} (x + 1)))) : 8 (arcsin (\frac{1}{2} (x + 1)) + \frac{1}{2} sin (2 arcsin (\frac{1}{2} (x + 1))))

= 8 (arcsin (\frac{1}{2} (x + 1)) + \frac{1}{2} sin (2 arcsin (\frac{1}{2} (x + 1))))

Add a constant to the solution

= 8 (arcsin (\frac{1}{2} (x + 1)) + \frac{1}{2} sin (2 arcsin (\frac{1}{2} (x + 1)))) + C

\int (x + 1) sin (n x) d x

\frac{d}{d x} (e^{- (\frac{x}{200})^{3.2}})

\int tan (4 x + 2) d x

\frac{t}{( 1 - t ^{2} ) ^{\frac{3}{2}}}

(2 y - 3 x) \frac{d y}{d x} = 3 y - 4 x

What is the integral of 4sqrt(3-2x-x^2) ?
The integral of 4sqrt(3-2x-x^2) is 8(arcsin(1/2 (x+1))+1/2 sin(2arcsin(1/2 (x+1))))+C