What is (\partial)/(\partial x)(e^{2z}-xyz) ?

The answer to (\partial)/(\partial x)(e^{2z}-xyz) is -zy

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(\partial)/(\partial x)(e^{2z}-xyz)

\frac{\partial}{\partial x} (e^{2 z} - x yz)

- zy

Solution steps

\frac{\partial}{\partial x} (e^{2 z} - x yz)

Treat

z, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{2 z}) - \frac{\partial}{\partial x} (x yz)

\frac{\partial}{\partial x} (e^{2 z}) = 0

\frac{\partial}{\partial x} (x yz) = zy

= 0 - zy

Simplify

= - zy

\int x 1 - x d x

9 y^{^{''}} - 81 y = 0

2 t^{3 π}

\int_{1}^{4} \frac{x - 1}{x} d x

\frac{1}{2} + 2 sin (x) + 2 cos (x)

What is (\partial)/(\partial x)(e^{2z}-xyz) ?
The answer to (\partial)/(\partial x)(e^{2z}-xyz) is -zy