What is (\partial)/(\partial x)(xz+yz) ?

The answer to (\partial)/(\partial x)(xz+yz) is z

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(\partial)/(\partial x)(xz+yz)

\frac{\partial}{\partial x} (x z + yz)

z

Solution steps

\frac{\partial}{\partial x} (x z + yz)

Treat

z, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x z) + \frac{\partial}{\partial x} (yz)

\frac{\partial}{\partial x} (x z) = z

\frac{\partial}{\partial x} (yz) = 0

= z + 0

Simplify

= z

\int sin^{10} (x) cos (x) d x

\int \frac{x - 3}{x} d x

\frac{d}{d x} (2 x^{2} + 8 x)

x (x^{2} - 11 x + 35), x^{2}

\frac{d}{d x} (\frac{3}{4} x^{12})

What is (\partial)/(\partial x)(xz+yz) ?
The answer to (\partial)/(\partial x)(xz+yz) is z