What is the derivative of cos(3^x) ?

The derivative of cos(3^x) is -sin(3^x)*3^xln(3)

What is the first derivative of cos(3^x) ?

The first derivative of cos(3^x) is -sin(3^x)*3^xln(3)

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derivative of

cos (3^{x})

- sin (3^{x}) \cdot 3^{x} ln (3)

Solution steps

\frac{d}{d x} (cos (3^{x}))

Apply the chain rule:

- sin (3^{x}) \frac{d}{d x} (3^{x})

= - sin (3^{x}) \frac{d}{d x} (3^{x})

\frac{d}{d x} (3^{x}) = 3^{x} ln (3)

= - sin (3^{x}) \cdot 3^{x} ln (3)

\frac{d}{d x} (\frac{1 - 2 x}{x})

\frac{d}{d x} (cos (x) - e^{x})

\int tan^{4} (\frac{x}{2}) sec^{4} (\frac{x}{2}) d x

\int \frac{1}{9 + y ^{2}} d y

\frac{\partial}{\partial x} (sin (\frac{w}{c} x) sin (wt))

What is the derivative of cos(3^x) ?
The derivative of cos(3^x) is -sin(3^x)*3^xln(3)
What is the first derivative of cos(3^x) ?
The first derivative of cos(3^x) is -sin(3^x)*3^xln(3)